A perfect gas at 27^{circ} C is heated at con | vedclass

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(D) According to Charles's Law,for a fixed mass of gas at constant pressure,the volume is directly proportional to its absolute temperature: $V \propt

Vedclass · Accepted Answer

$300$

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(D) According to Charles's Law,for a fixed mass of gas at constant pressure,the volume is directly proportional to its absolute temperature: $V \propto T$ or $\frac{V_1}{T_1} = \frac{V_2}{T_2}$.Given initial temperature $T_1 = 27^{\circ} C = 27 + 273 = 300 \ K$.Let initial volume $V_1 = V$. Then final volume $V_2 = 2V$.Substituting these values into the formula: $\frac{V}{300} = \frac{2V}{T_2}$.Solving for $T_2$: $T_2 = 300 	imes 2 = 600 \ K$.Converting the final temperature to Celsius: $T_2 = 600 - 273 = 327^{\circ} C$.The increase in temperature is $\Delta T = T_2 - T_1 = 327^{\circ} C - 27^{\circ} C = 300^{\circ} C$.

$A$ perfect gas at $27^{\circ} C$ is heated at constant pressure so as to double its volume. The increase in temperature of the gas will be (in $^{\circ} C$)

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