n-Propyl chloride reacts with sodium metal in | vedclass

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Question

(A) This reaction is an example of the $Wurtz$ reaction,where alkyl halides react with sodium metal in the presence of dry ether to form higher alkane

Vedclass · Accepted Answer

$CH_{3}CH_{2}CH_{2}CH_{2}CH_{2}CH_{3}$

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(A) This reaction is an example of the $Wurtz$ reaction,where alkyl halides react with sodium metal in the presence of dry ether to form higher alkanes.$2 CH_{3}CH_{2}CH_{2}Cl + 2 Na \xrightarrow{	ext{dry ether}} CH_{3}CH_{2}CH_{2}CH_{2}CH_{2}CH_{3} + 2 NaCl$As $n$-propyl chloride $(CH_{3}CH_{2}CH_{2}Cl)$ is used,the product formed is $n$-hexane $(CH_{3}CH_{2}CH_{2}CH_{2}CH_{2}CH_{3})$.

$n$-Propyl chloride reacts with sodium metal in dry ether to give:

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