(A) To prepare $2-$methylpropane by the Wurtz reaction,we need to couple a methyl group with an isopropyl group. Therefore,the haloalkanes required ar

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chloromethane and $2-$chloropropane

(A) To prepare $2-$methylpropane by the Wurtz reaction,we need to couple a methyl group with an isopropyl group. Therefore,the haloalkanes required are chloromethane $(CH_3Cl)$ and $2-$chloropropane $(CH_3CHClCH_3)$.The reaction is as follows:$CH_3Cl + CH_3CHClCH_3 + 2Na \xrightarrow{\text{dry ether}} CH_3CH(CH_3)CH_3 + 2NaCl$Thus,the correct option is $A$.

Class 12 Chemistry Haloalkanes and Haloarenes Preparation of Haloalkanes

Medium

$2-$methylpropane can be prepared by the Wurtz reaction. The haloalkanes taken along with metallic sodium and dry ether are:

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A
chloromethane and $2-$chloropropane
B
chloroethane and chloromethane
C
chloroethane and $1-$chloropropane
D
chloromethane and $1-$chloropropane

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Class 12

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Haloalkanes and Haloarenes

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Preparation of Haloalkanes

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In the replacement reaction:
$R-Cl + MF \rightarrow R-F + MCl$
The reaction will be most favourable if $M$ happens to be:

MediumAIPMT 2012

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How many pairs of enantiomers are obtained from the monochlorination of $2,3-$dimethylbutane?

Medium

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Assertion : Alkyl iodide can be prepared by treating alkyl chloride/bromide with $NaI$ in acetone.
Reason : $NaCl/NaBr$ are soluble in acetone while $NaI$ is not.

DifficultAIIMS 2007

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The starting substance for the preparation of $CH_3I$ is

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Alkyl halides can be converted into Grignard reagents by:

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$2-$methylpropane can be prepared by the Wurtz reaction. The haloalkanes taken along with metallic sodium and dry ether are:

Similar Questions

In the replacement reaction:$R-Cl + MF \rightarrow R-F + MCl$The reaction will be most favourable if $M$ happens to be:

How many pairs of enantiomers are obtained from the monochlorination of $2,3-$dimethylbutane?

Assertion : Alkyl iodide can be prepared by treating alkyl chloride/bromide with $NaI$ in acetone.Reason : $NaCl/NaBr$ are soluble in acetone while $NaI$ is not.

The starting substance for the preparation of $CH_3I$ is

Alkyl halides can be converted into Grignard reagents by:

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Online Exam Module

In the replacement reaction:
$R-Cl + MF \rightarrow R-F + MCl$
The reaction will be most favourable if $M$ happens to be:

Assertion : Alkyl iodide can be prepared by treating alkyl chloride/bromide with $NaI$ in acetone.
Reason : $NaCl/NaBr$ are soluble in acetone while $NaI$ is not.