(C) $H_2O_2$ acts as an oxidizing agent in many reactions. $H_2O_2$ oxidizes $PbS$ to $PbSO_4$,$Na_2SO_3$ to $Na_2SO_4$,and $KI$ to $I_2$. However,$H_

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(C) $H_2O_2$ acts as an oxidizing agent in many reactions. $H_2O_2$ oxidizes $PbS$ to $PbSO_4$,$Na_2SO_3$ to $Na_2SO_4$,and $KI$ to $I_2$. However,$H_2O_2$ reacts with $O_3$ to form $H_2O$ and $O_2$ $(H_2O_2 + O_3 \rightarrow H_2O + 2O_2)$. In this reaction,$O_3$ is reduced to $O_2$,and $H_2O_2$ acts as a reducing agent,not an oxidizing agent.