E_{1}, E_{2}, E_{3} are the EMF values of thr | vedclass

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(B) The Nernst equation for the cell reaction is $E_{	ext{cell}} = E_{	ext{cell}}^{\circ} - \frac{0.0591}{2} \log \frac{[Zn^{2+}]}{[Cu^{2+}]}$.$(I)

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$E_{3} > E_{2} > E_{1}$

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(B) The Nernst equation for the cell reaction is $E_{	ext{cell}} = E_{	ext{cell}}^{\circ} - \frac{0.0591}{2} \log \frac{[Zn^{2+}]}{[Cu^{2+}]}$.$(I) E_{1} = E_{	ext{cell}}^{\circ} - \frac{0.0591}{2} \log \frac{1}{0.1} = E_{	ext{cell}}^{\circ} - \frac{0.0591}{2} \log(10) = E_{	ext{cell}}^{\circ} - 0.02955 \ V$.$(II) E_{2} = E_{	ext{cell}}^{\circ} - \frac{0.0591}{2} \log \frac{1}{1} = E_{	ext{cell}}^{\circ} - 0 = E_{	ext{cell}}^{\circ}$.$(III) E_{3} = E_{	ext{cell}}^{\circ} - \frac{0.0591}{2} \log \frac{0.1}{1} = E_{	ext{cell}}^{\circ} - \frac{0.0591}{2} \log(10^{-1}) = E_{	ext{cell}}^{\circ} + 0.02955 \ V$.Comparing the values,we get $E_{3} > E_{2} > E_{1}$.

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