A current of 5 ~A is flowing at 220 ~V in the | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) Given: Primary voltage $V_{p} = 220 ~V$,Primary current $I_{p} = 5 ~A$,Secondary voltage $V_{s} = 2200 ~V$,Power loss $= 50 \%$.Efficiency $\eta =

Vedclass · Accepted Answer

$0.25$

Vedclass · Answer

(C) Given: Primary voltage $V_{p} = 220 ~V$,Primary current $I_{p} = 5 ~A$,Secondary voltage $V_{s} = 2200 ~V$,Power loss $= 50 \%$.Efficiency $\eta = 100 \% - 50 \% = 50 \%$.The efficiency of a transformer is defined as the ratio of output power to input power:$\eta = \frac{P_{out}}{P_{in}} = \frac{V_{s} I_{s}}{V_{p} I_{p}}$Substituting the given values:$0.5 = \frac{2200 	imes I_{s}}{220 	imes 5}$$0.5 = \frac{2200 	imes I_{s}}{1100}$$0.5 = 2 	imes I_{s}$$I_{s} = \frac{0.5}{2} = 0.25 ~A$.Therefore,the current in the secondary coil is $0.25 ~A$.

$A$ current of $5 ~A$ is flowing at $220 ~V$ in the primary coil of a transformer. If the voltage produced in the secondary coil is $2200 ~V$ and $50 \%$ of power is lost,then the current in the secondary coil will be: (in $~A$)

Similar Questions

If $\frac{d^2y}{dx^2} = 0$,then

Let $f$ be defined on $D = \mathbb{R} - \{-1, 1\}$ by $f(x) = \frac{|x|}{1-|x|}$,then

The work function of a substance is $4.0 \, eV$. The longest wavelength of light that can cause photoelectron emission from this substance is approximately ............ $nm$.

The area (in sq units) of the quadrilateral formed by two pairs of lines $\lambda^2 x^2 - m^2 y^2 - n(\lambda x + m y) = 0$ and $\lambda^2 x^2 - m^2 y^2 + n(\lambda x + m y) = 0$ is:

Which of the following is not hydrolysed?

Vedclass Test Series

Exam Paper Generator

Online Exam Module