CH_3-CH=CH-CH_2OH xrightarrow{PCC} CH_3-CH=CH | vedclass

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(B) In the reactant $CH_3-CH=CH-CH_2OH$,the carbon atom at position $C-1$ is bonded to two hydrogen atoms,one oxygen atom,and one carbon atom. It is $

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$sp^3$ to $sp^2$

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(B) In the reactant $CH_3-CH=CH-CH_2OH$,the carbon atom at position $C-1$ is bonded to two hydrogen atoms,one oxygen atom,and one carbon atom. It is $sp^3$ hybridised.In the product $CH_3-CH=CH-CHO$,the carbon atom at position $C-1$ is part of the aldehyde group $(-CHO)$,where it forms a double bond with oxygen. It is $sp^2$ hybridised.Therefore,the hybridisation of $C-1$ changes from $sp^3$ to $sp^2$.

$CH_3-CH=CH-CH_2OH \xrightarrow{PCC} CH_3-CH=CH-CHO$
What is the change in hybridisation at $C-1$ in the above reaction?

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$CH_3-CH=CH-CH_2OH \xrightarrow{PCC} CH_3-CH=CH-CHO$What is the change in hybridisation at $C-1$ in the above reaction?