(B) In single-slit diffraction,the condition for the first minimum (where the light is diffracted) is given by the formula $a \sin \theta = n \lambda$

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(B) In single-slit diffraction,the condition for the first minimum (where the light is diffracted) is given by the formula $a \sin \theta = n \lambda$. For the first minimum,we take $n = 1$,so $a \sin \theta = \lambda$. Since the angle $\theta$ is very small,we can approximate $\sin \theta \approx \theta$. Therefore,$a \theta \approx \lambda$,which gives $\theta \approx \frac{\lambda}{a}$. Thus,the angle of diffraction is approximately $\frac{\lambda}{a}$.

Class 12 Physics Wave Optics Single Slit Diffraction of Light

Easy

$A$ slit of size '$a$' is illuminated by a parallel beam of light of wavelength $\lambda$. The angle at which this light is diffracted is approximately . . . . . . .

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A
$\frac{\lambda}{a^{2}}$
B
$\frac{\lambda}{a}$
C
$\frac{a^{2}}{\lambda}$
D
$\frac{a}{\lambda}$

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Wave Optics

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Single Slit Diffraction of Light

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$A$ slit of width $a$ is illuminated by monochromatic light of wavelength $650 \ nm$. The value of the slit width $a$ when the first minimum is formed at a diffraction angle of $30^\circ$ is:

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Obtain the formulas for the angular width and linear width of the central maximum in a single-slit diffraction experiment.

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In the experiment of diffraction due to a single slit,if the slit width is decreased,the width of the central maximum

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$A$ parallel beam of monochromatic light of wavelength $600 \,nm$ passes through a single slit of $0.4 \,mm$ width. The angular divergence corresponding to the second-order minima would be $...... \times 10^{-3} \,rad$.

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The width of the $nth$ $HPZ$ (Half Period Zone) will be:

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$A$ slit of size '$a$' is illuminated by a parallel beam of light of wavelength $\lambda$. The angle at which this light is diffracted is approximately . . . . . . .

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$A$ slit of width $a$ is illuminated by monochromatic light of wavelength $650 \ nm$. The value of the slit width $a$ when the first minimum is formed at a diffraction angle of $30^\circ$ is:

Obtain the formulas for the angular width and linear width of the central maximum in a single-slit diffraction experiment.

In the experiment of diffraction due to a single slit,if the slit width is decreased,the width of the central maximum

$A$ parallel beam of monochromatic light of wavelength $600 \,nm$ passes through a single slit of $0.4 \,mm$ width. The angular divergence corresponding to the second-order minima would be $...... \times 10^{-3} \,rad$.

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