(A) The power of a lens is given by the formula $P = \frac{1}{f}$,where $f$ is the focal length in meters.Given power $P = -4.0 \text{ D}$.Since the p

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Concave lens of focal length $-25.0 \text{ cm}$

(A) The power of a lens is given by the formula $P = \frac{1}{f}$,where $f$ is the focal length in meters.Given power $P = -4.0 \text{ D}$.Since the power is negative,the lens is a concave lens.Using the formula $f = \frac{1}{P}$,we get:$f = \frac{1}{-4.0} \text{ m} = -0.25 \text{ m}$.Converting meters to centimeters: $f = -0.25 \times 100 \text{ cm} = -25.0 \text{ cm}$.Therefore,it is a concave lens with a focal length of $-25.0 \text{ cm}$.

Class 12 Physics Ray Optics and Optical Instruments Refraction by Lenses

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$A$ lens has a power of $-4.0 \text{ Diopter}$. This means . . . . . . .

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A
Concave lens of focal length $-25.0 \text{ cm}$
B
Concave lens of focal length $-0.25 \text{ cm}$
C
Concave lens of focal length $+0.25 \text{ cm}$
D
Concave lens of focal length $+25.0 \text{ cm}$

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Ray Optics and Optical Instruments

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Refraction by Lenses

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An object of height $1.5 \ cm$ is placed on the axis of a convex lens of focal length $25 \ cm$. $A$ real image is formed at a distance of $75 \ cm$ from the lens. The size of the image will be........$cm$.

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An object approaches a convergent lens from the left of the lens with a uniform speed $5 \ m/s$ and stops at the focus. The image :-

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$A$ lens has a power of $-4.0 \text{ Diopter}$. This means . . . . . . .

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$A$ thin glass (refractive index $1.5$) lens has an optical power of $-5\,D$ in air. Its optical power in a liquid medium with a refractive index of $1.6$ will be:

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