A cross was made by Mendel with pea plants be | vedclass

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(C) In a dihybrid cross involving two traits (flower color and flower position),the $F_1$ generation produces dihybrid plants with the genotype $VvAa$

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$4$

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(C) In a dihybrid cross involving two traits (flower color and flower position),the $F_1$ generation produces dihybrid plants with the genotype $VvAa$. When these $F_1$ individuals are self-crossed to produce the $F_2$ generation,the phenotypic ratio follows the Mendelian dihybrid ratio of $9:3:3:1$. The traits are: $9$ (Violet,Axial) $3$ (Violet,Terminal) $3$ (White,Axial) $1$ (White,Terminal) White flowers are recessive $(vv)$. In the $F_2$ generation,the total proportion of white-flowered plants is the sum of those that are white-axial and white-terminal,which is $3/16 + 1/16 = 4/16$ (or $1/4$). Therefore,the phenotypic ratio of white flowers is $4/16$.

$A$ cross was made by Mendel with pea plants between violet flowers $(VV)$ in axial position $(AA)$ and white flowers $(vv)$ in terminal position $(aa)$. What phenotypic ratio of white flowers $(vv)$ did he receive in the $F_2$ generation (in $/16$)?

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