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(B) The velocity $v$ of the particle can be resolved into two components: one parallel to the magnetic field $(v_{\parallel} = v \cos 	heta)$ and one

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helical

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(B) The velocity $v$ of the particle can be resolved into two components: one parallel to the magnetic field $(v_{\parallel} = v \cos 	heta)$ and one perpendicular to the magnetic field $(v_{\perp} = v \sin 	heta)$.Due to the parallel component $v_{\parallel}$,the particle moves linearly along the direction of the magnetic field.Due to the perpendicular component $v_{\perp}$,the magnetic force $F = q(v 	imes B)$ acts as a centripetal force,causing the particle to move in a circular path in the plane perpendicular to the field.The combination of linear motion along the field and circular motion perpendicular to the field results in a helical path.

$A$ particle of mass $m$ and charge $q$ is incident on the $XZ$ plane with velocity $v$ in a direction making an angle $\theta$ with a uniform magnetic field applied along the $X$-axis. The nature of motion performed by the particle is . . . . . . .

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