A solenoid of length 0.25 m has a radius of | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The magnetic field $B$ inside a long solenoid is given by the formula $B = \mu_0 n I$, where $n = N/l$ is the number of turns per unit length.Give

Vedclass · Accepted Answer

$6.28 	imes 10^{-3} \ T$

Vedclass · Answer

(A) The magnetic field $B$ inside a long solenoid is given by the formula $B = \mu_0 n I$, where $n = N/l$ is the number of turns per unit length.Given:Length $l = 0.25 \ m$Number of turns $N = 500$Current $I = 2.5 \ A$Permeability $\mu_0 = 4 \pi 	imes 10^{-7} \ T \cdot m/A$Calculation:$n = \frac{500}{0.25} = 2000 \ turns/m$$B = (4 \pi 	imes 10^{-7}) 	imes 2000 	imes 2.5$$B = 4 	imes 3.14 	imes 10^{-7} 	imes 5000$$B = 12.56 	imes 10^{-4} \ T = 6.28 	imes 2 	imes 10^{-4} \ T = 6.28 	imes 10^{-3} \ T$.

$A$ solenoid of length $0.25 \ m$ has a radius of $1 \ cm$ and is made up of $500$ turns. It carries a current of $2.5 \ A$. What is the magnitude of the magnetic field inside the solenoid? (Take $\mu_0 = 4 \pi \times 10^{-7} \ SI$ units).

Similar Questions

The magnetic field $B$ within a solenoid having $n$ turns per meter length and carrying a current of $i$ amperes is given by:

Ampere's law is true for which type of current?

An infinitely long cylindrical wire of radius $a$ carries a steady current $I$ uniformly distributed across its cross-section. Determine the magnetic field $B$ at a distance $r$ from the axis for: $(a) r > a$,$(b) r = a$,$(c) r < a$,and $(d)$ at the axis $(r = 0)$.

$A$ current $i$ flows in an infinitely long,straight and thin-walled pipe. Then,

What is an Amperian loop?

Vedclass Test Series

Exam Paper Generator

Online Exam Module