E. coli has 4.6 times 10^6 text{ bp}, its rat | vedclass

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(C) The genome of $E. coli$ contains $4.6 	imes 10^6 	ext{ bp}$.$E. coli$ completes its replication process in approximately $38$ minutes ($2280$ se

Vedclass · Accepted Answer

$2000$

Vedclass · Answer

(C) The genome of $E. coli$ contains $4.6 	imes 10^6 	ext{ bp}$.$E. coli$ completes its replication process in approximately $38$ minutes ($2280$ seconds).The rate of replication is calculated as:$	ext{Rate} = \frac{	ext{Total base pairs}}{	ext{Total time in seconds}}$$	ext{Rate} = \frac{4.6 	imes 10^6}{2280} \approx 2017 	ext{ bp/second}$.Rounding this to the nearest standard value provided in the options, we get $2000 	ext{ bp/second}$.

$E. coli$ has $4.6 \times 10^6 \text{ bp}$, its rate of multiplication during replication is about $ . . . . . . $ per second. (in $\text{ bp}$)

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