Class 12PhysicsMagnetism and MatterMagnetic field due to magnetic dipole and Dipole in Magnetic Field and Poential Energy and Work Done
Easy$A$ short bar magnet placed with its axis at $30^{\circ}$ to a uniform external magnetic field of $0.5 \ T$ experiences a torque of magnitude equal to $4.5 \times 10^{-2} \ J$. The magnitude of the magnetic moment is . . . . . . .
- A$3.6 \times 10^2 \ J \ T^{-1}$
- B$36 \times 10^{-2} \ J \ T^{-1}$
- C$1.8 \times 10^2 \ J \ T^{-1}$
- D$18 \times 10^{-2} \ J \ T^{-1}$
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Similar Questions
The figure shows a bar magnet and a long straight wire $W$,carrying current into the plane of the paper. Point $P$ is the point of intersection of the axis of the magnet and the line of shortest distance between the magnet and the wire. If $P$ is the midpoint of the magnet,then which of the following statements is correct?
Write an expression for the magnitude of the magnetic field at a point lying on the equatorial line of a bar magnet.
Easy
View SolutionWhat is the magnitude of the equatorial magnetic field due to a bar magnet of length $5.0 \ cm$ at a distance $75 \ cm$ from its midpoint? The magnetic moment of the bar magnet is $0.75 \ A \ m^2$.
If a bar magnet of magnetic moment $M$ is freely suspended in a uniform magnetic field of strength $B$,the work done in rotating the magnet through an angle $\theta$ is
Medium
View Solution$A$ short bar magnet placed with its axis at $30^{\circ}$ with an external field of $800 G$ experiences a torque of $0.016 Nm$. The magnetic moment of the bar magnet is (in $Am^2$)
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