A 50 mu F capacitor is connected to a 110 V, | vedclass

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(D) Given: Capacitance $C = 50 \mu F = 50 	imes 10^{-6} F$,Voltage $V_{rms} = 110 V$,Frequency $
u = 60 Hz$.First,calculate the capacitive reactance

Vedclass · Accepted Answer

$2.1$

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(D) Given: Capacitance $C = 50 \mu F = 50 	imes 10^{-6} F$,Voltage $V_{rms} = 110 V$,Frequency $
u = 60 Hz$.First,calculate the capacitive reactance $X_C$ using the formula $X_C = \frac{1}{2 \pi 
u C}$.$X_C = \frac{1}{2 	imes 3.1416 	imes 60 	imes 50 	imes 10^{-6}} \approx 53.05 \Omega$.The rms current $I_{rms}$ is given by $I_{rms} = \frac{V_{rms}}{X_C}$.$I_{rms} = \frac{110}{53.05} \approx 2.07 A$.Rounding to one decimal place,we get $I_{rms} = 2.1 A$.

$A$ $50 \mu F$ capacitor is connected to a $110 V, 60 Hz$ $AC$ supply. Determine the rms value of the current in the circuit. (in $A$)

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