$41$ tuning forks are arranged in increasing order of frequency such that each produces $5 \text{ beats/second}$ with the next tuning fork. If the frequency of the last tuning fork is double that of the frequency of the first fork,then the frequency of the first and last fork is:

$16$ tuning forks are arranged in the order of increasing frequencies. Any two successive forks give $8$ beats per second when sounded together. If the frequency of the last fork is twice the first,then the frequency of the first fork is:

The frequencies of three tuning forks $A$,$B$,and $C$ are related as $n_{A} > n_{B} > n_{C}$. When the forks $A$ and $B$ are sounded together,the number of beats produced per second is $n_1$. When forks $A$ and $C$ are sounded together,the number of beats produced per second is $n_2$. How many beats are produced per second when forks $B$ and $C$ are sounded together?

The disc of a siren containing $60$ holes rotates at a constant speed of $360\,rpm$. The emitted sound is in unison with a tuning fork of frequency .... $Hz$

$A$ tuning fork of frequency $480 \ Hz$ produces $10$ beats per second when sounded with a vibrating sonometer string. What must have been the frequency of the string if a slight increase in tension produces fewer beats per second than before?

$A$ tuning fork $A$ produces $5$ beats per second with a tuning fork of frequency $480 \ Hz$. When a little wax is stuck to a prong of fork $A$,the number of beats heard per second becomes $2$. What is the frequency of tuning fork $A$ before the wax is stuck to it (in $Hz$)?