A string of mass M is under a tension T. The | vedclass

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(A) The velocity of a transverse wave on a string is given by $v = \sqrt{\frac{T}{\mu}}$,where $T$ is the tension and $\mu$ is the mass per unit lengt

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$\sqrt{\frac{L M}{T}}$

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(A) The velocity of a transverse wave on a string is given by $v = \sqrt{\frac{T}{\mu}}$,where $T$ is the tension and $\mu$ is the mass per unit length of the string,defined as $\mu = \frac{M}{L}$.Substituting $\mu$ into the velocity formula,we get $v = \sqrt{\frac{T}{M/L}} = \sqrt{\frac{TL}{M}}$.The time $t$ required for the disturbance to travel the length $L$ of the string is given by $t = \frac{L}{v}$.Substituting the expression for $v$,we get $t = \frac{L}{\sqrt{TL/M}} = L \sqrt{\frac{M}{TL}} = \sqrt{\frac{L^2 M}{TL}} = \sqrt{\frac{LM}{T}}$.

$A$ string of mass $M$ is under a tension $T$. The length of the string is $L$. $A$ transverse wave starts at one end of the string. The time required for the disturbance to reach the other end is

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