$A$ pipe closed at one end has a length of $0.8 \ m$. At its open end,a $0.5 \ m$ long uniform string is vibrating in its second harmonic and it resonates with the fundamental frequency of the pipe. If the tension in the wire is $50 \ N$ and the speed of sound is $320 \ m/s$,the mass of the string is: (in $g$)

  • A
    $8$
  • B
    $2$
  • C
    $10$
  • D
    $4$

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$(a)$ The wave is travelling to the left.
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$(i) \, y_1 = A \cos 2\pi \left( n_1 t + \frac{x}{\lambda_1} \right)$
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