A parallel beam of light of wavelength lambda | vedclass

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(B) The condition for the $n^{	ext{th}}$ diffraction minimum is given by the path difference $\Delta x = n\lambda$,where $n = 1, 2, 3, \dots$ is the

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$4 \pi$

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(B) The condition for the $n^{	ext{th}}$ diffraction minimum is given by the path difference $\Delta x = n\lambda$,where $n = 1, 2, 3, \dots$ is the order of the minimum.For the second minimum,we set $n = 2$,which gives the path difference $\Delta x = 2\lambda$.The relationship between phase difference $\phi$ and path difference $\Delta x$ is given by $\phi = \frac{2\pi}{\lambda} \Delta x$.Substituting the value of $\Delta x$ for the second minimum:$\phi = \frac{2\pi}{\lambda} (2\lambda) = 4\pi$.Therefore,the phase difference between the rays coming from the two edges of the slit at the second minimum is $4\pi$.

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