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(B) The voltage gain $(A_v)$ of a common emitter amplifier is given by the formula: $A_v = \beta 	imes \frac{R_L}{R_i}$,where $\beta = \frac{\Delta I

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$1000$

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(B) The voltage gain $(A_v)$ of a common emitter amplifier is given by the formula: $A_v = \beta 	imes \frac{R_L}{R_i}$,where $\beta = \frac{\Delta I_C}{\Delta I_B}$.Given:Load resistance $(R_L)$ = $2 \ k\Omega = 2000 \ \Omega$.Input resistance $(R_i)$ = $150 \ \Omega$.Change in base current $(\Delta I_B)$ = $20 \ \mu A = 20 	imes 10^{-6} \ A$.Change in collector current $(\Delta I_C)$ = $1.5 \ mA = 1.5 	imes 10^{-3} \ A$.First,calculate the current gain $(\beta)$:$\beta = \frac{1.5 	imes 10^{-3}}{20 	imes 10^{-6}} = \frac{1.5}{20} 	imes 10^3 = 0.075 	imes 1000 = 75$.Now,calculate the voltage gain $(A_v)$:$A_v = 75 	imes \frac{2000}{150} = 75 	imes \frac{40}{3} = 25 	imes 40 = 1000$.

$A$ transistor is used as a common emitter amplifier with a load resistance of $2 \ k\Omega$. The input resistance is $150 \ \Omega$. Base current is changed by $20 \ \mu A$,which results in a change in collector current by $1.5 \ mA$. The voltage gain of the amplifier is

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