$A$ door $1.2 \,m$ wide requires a force of $1 \,N$ to be applied perpendicularly at the free end to open or close it. The perpendicular force required at a point $0.2 \,m$ distant from the hinges for opening or closing the door is: (in $\,N$)
- A$2.4$
- B$3.6$
- C$6.0$
- D$1.2$
Explore More
Similar Questions
$A$ tap can be easily opened or closed with the help of two fingers because:
Easy
View SolutionShow that the moment of a couple does not depend on the point about which you take the moments.
Easy
View SolutionWhich type of motion exists due to the moment of force (couple)?
Easy
View Solution$A$ couple produces
Medium
View Solution$A$ wheel of radius $20\, cm$ has forces applied to it as shown in the figure. The net torque produced by the forces $4\, N$ at $A$,$8\, N$ at $B$,$6\, N$ at $C$,and $9\, N$ at $D$ at the angles indicated is:
Difficult
View SolutionVedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo