$A$ light ray of frequency '$v$' and wavelength '$\lambda$' enters a liquid of refractive index $\frac{3}{2}$. The ray travels in the liquid with:

  • A
    frequency $v$ and wavelength $\left(\frac{2}{3}\right) \lambda$
  • B
    frequency $v$ and wavelength $\left(\frac{3}{2}\right) \lambda$
  • C
    frequency $\left(\frac{3}{2}\right) v$ and wavelength $\lambda$
  • D
    frequency $\left(\frac{2}{3}\right) v$ and wavelength $\left(\frac{2}{3}\right) \lambda$

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The angle of incidence is found to be twice the angle of refraction when a ray of light passes from vacuum into a medium of refractive index $\mu$. The angle of incidence will be

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$A$ ray of light travelling in a medium of refractive index $\mu$ is incident at an angle $\theta$ on a composite transparent plate consisting of $50$ plates of refractive indices $1.01\mu, 1.02\mu, 1.03\mu, \dots, 1.50\mu$. The ray emerges from the composite plate into a medium of refractive index $1.6\mu$ at an angle $x$. Then:

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The difference of speed of light in the two media $A$ and $B$ $(v_{A}-v_{B})$ is $2.6 \times 10^{7} \, m/s$. If the refractive index of medium $B$ is $1.47$,then the ratio of refractive index of medium $B$ to medium $A$ is: (Given: speed of light in vacuum $c = 3 \times 10^{8} \, m/s$)

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