A thin prism P_{1} with angle 4^{circ} and ma | vedclass

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(D) For a thin prism,the angle of deviation is given by $\delta = A(n - 1)$.For dispersion without deviation,the net deviation must be zero,which mean

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$3$

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(D) For a thin prism,the angle of deviation is given by $\delta = A(n - 1)$.For dispersion without deviation,the net deviation must be zero,which means the deviation produced by the first prism must be equal to the deviation produced by the second prism in the opposite direction.Therefore,$\delta_{1} = \delta_{2}$.Substituting the formula,we get $A_{1}(n_{1} - 1) = A_{2}(n_{2} - 1)$.Given $A_{1} = 4^{\circ}$,$n_{1} = 1.54$,and $n_{2} = 1.72$.$4(1.54 - 1) = A_{2}(1.72 - 1)$.$4 	imes 0.54 = A_{2} 	imes 0.72$.$A_{2} = \frac{4 	imes 0.54}{0.72} = \frac{2.16}{0.72} = 3^{\circ}$.

$A$ thin prism $P_{1}$ with angle $4^{\circ}$ and made from glass of refractive index $1.54$ is combined with another thin prism $P_{2}$ made from glass of refractive index $1.72$ to produce dispersion without deviation. The angle of prism for $P_{2}$ is (in $^{\circ}$)

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