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(D) The resolving power of a telescope is given by the formula $RP = \frac{D}{1.22 \lambda}$,where $D$ is the diameter of the objective lens and $\lam

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high

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(D) The resolving power of a telescope is given by the formula $RP = \frac{D}{1.22 \lambda}$,where $D$ is the diameter of the objective lens and $\lambda$ is the wavelength of light used.From this relation,it is clear that the resolving power is directly proportional to the diameter of the objective lens $(RP \propto D)$.Therefore,if the telescope has a large diameter of the objective,its resolving power will be high.

$A$ telescope has a large diameter of the objective. Then,its resolving power is

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