A concave mirror of focal length 'f' produces | vedclass

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(C) For a concave mirror, the magnification $m$ for a real image is negative, so $m = -n$.By definition of magnification, $m = -\frac{v}{u}$, where $v

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$\left(\frac{n+1}{n}\right) f$

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(C) For a concave mirror, the magnification $m$ for a real image is negative, so $m = -n$.By definition of magnification, $m = -\frac{v}{u}$, where $v$ is the image distance and $u$ is the object distance.Thus, $-n = -\frac{v}{u} \implies v = nu$.Using the mirror formula: $\frac{1}{f} = \frac{1}{v} + \frac{1}{u}$.Since the mirror is concave, the focal length $f$ is negative, i.e., $-f$. The object distance $u$ is also negative, i.e., $-u$.Substituting these values: $\frac{1}{-f} = \frac{1}{-nu} + \frac{1}{-u}$.Multiplying by $-1$: $\frac{1}{f} = \frac{1}{nu} + \frac{1}{u} = \frac{1+n}{nu}$.Rearranging for $u$: $u = \left(\frac{n+1}{n}\right) f$.

$A$ concave mirror of focal length '$f$' produces an image '$n$' times the size of the object. If the image is real, then the distance of the object from the mirror is

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