$A$ thin circular ring of mass $M$ and radius $r$ is rotating about its axis with an angular speed $\omega$. Two particles each of mass $m$ are now attached at diametrically opposite points. The angular speed of the ring will become

  • A
    $\frac{\omega M}{M+2m}$
  • B
    $\frac{\omega M}{M+m}$
  • C
    $\frac{\omega(M-2m)}{M}$
  • D
    $\frac{\omega(M-2m)}{M+2m}$

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