$A$ liquid drop of density $\rho$ is floating half-immersed in a liquid of density $d$. If $T$ is the surface tension,then the diameter of the liquid drop is ($g$ = acceleration due to gravity).

  • A
    $\left[\frac{6T}{g(2\rho-d)}\right]^{1/2}$
  • B
    $\left[\frac{8T}{3g(2\rho-d)}\right]^{1/2}$
  • C
    $\left[\frac{12T}{g(2\rho-d)}\right]^{1/2}$
  • D
    $\left[\frac{3T}{g(2\rho-d)}\right]^{1/2}$

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