$A$ horizontal wire of mass $m$,length $l$,and resistance $R$ is sliding on vertical rails in a uniform magnetic field $B$ directed perpendicularly. The terminal speed of the wire as it falls under the force of gravity is ($g =$ acceleration due to gravity).
- A$\frac{mgl}{BR}$
- B$\frac{B^2 l^2}{mgR}$
- C$\frac{mgR}{Bl}$
- D$\frac{mgR}{B^2 l^2}$
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