$A$ wire of length $L$ carries a current $I$. If the wire is turned into a square coil of single turn,the maximum magnitude of the torque in a given magnetic field $\overrightarrow{B}$ is

$A$ circular loop of area $0.01\,m^2$ carrying a current of $10\,A$ is held perpendicular to a magnetic field of intensity $0.1\,T$. The torque acting on the loop is......$N-m$.

$A$ uniform magnetic field of $3000\,G$ is established in the positive $z-$ direction. $A$ rectangular loop of sides $10\,cm$ and $5\,cm$ carries a current of $12\,A$. The loop is placed in the $xy-$ plane as shown in the figure. What is the magnitude of the torque on the loop?

$A$ closely wound solenoid of $2000$ turns and area of cross-section $1.5 \times 10^{-4} \, m^2$ carries a current of $2.0 \, A$. It is suspended through its centre and perpendicular to its length,allowing it to turn in a horizontal plane in a uniform magnetic field of $5 \times 10^{-2} \, T$ making an angle of $30^o$ with the axis of the solenoid. The torque on the solenoid will be:

$A$ circular coil of $30$ turns and radius $8 \,cm$ carrying a current of $6 \,A$ is suspended vertically in a uniform horizontal magnetic field of magnitude $1.0 \,T$. The field lines make an angle of $20^{\circ}$ with the normal of the coil. The magnitude of the counter torque that must be applied to prevent the coil from turning is (in $\,Nm$)

$A$ current-carrying coil is subjected to a uniform magnetic field. The coil will orient itself so that its plane becomes