A van is moving with a speed of 108 ,km/hr on | vedclass

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(B) The correct option is $B$.Concept: For safe driving on a level road, the centripetal force required for turning must be provided by the static fri

Vedclass · Accepted Answer

$180$

Vedclass · Answer

(B) The correct option is $B$.Concept: For safe driving on a level road, the centripetal force required for turning must be provided by the static friction between the tyres and the road. If the centripetal force exceeds the maximum limiting friction, the vehicle will skid.Mathematically, the condition for safe turning is $\frac{mv^2}{r} \leq \mu mg$.Given: Velocity $v = 108 \,km/hr = 108 	imes \frac{5}{18} \,m/s = 30 \,m/s$, coefficient of friction $\mu = 0.5$, and $g = 10 \,m/s^2$.To find the minimum radius $r_{\min}$, we use the equality condition: $r_{\min} = \frac{v^2}{\mu g}$.Substituting the values: $r_{\min} = \frac{30^2}{0.5 	imes 10} = \frac{900}{5} = 180 \,m$.

$A$ van is moving with a speed of $108 \,km/hr$ on a level road where the coefficient of friction between the tyres and the road is $0.5$. For the safe driving of the van, the minimum radius of curvature of the road shall be (Acceleration due to gravity, $g = 10 \,m/s^2$) (in $\,m$)

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