A conducting sphere of radius R is given a ch | vedclass

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Question

(A) For a conducting sphere,the charge $Q$ resides entirely on its outer surface.Inside a conducting sphere,the electric field $E$ is zero everywhere

Vedclass · Accepted Answer

zero and $\frac{Q}{4 \pi \epsilon_0 R}$

Vedclass · Answer

(A) For a conducting sphere,the charge $Q$ resides entirely on its outer surface.Inside a conducting sphere,the electric field $E$ is zero everywhere because there is no enclosed charge $(q_{enclosed} = 0)$ according to Gauss's Law.Since the electric field is zero inside the sphere,the potential $V$ is constant throughout the interior and is equal to the potential at the surface.The potential at the surface (and thus at the centre) is given by $V = \frac{Q}{4 \pi \epsilon_0 R}$.Therefore,the electric field at the centre is $0$ and the electric potential at the centre is $\frac{Q}{4 \pi \epsilon_0 R}$.

$A$ conducting sphere of radius $R$ is given a charge $Q$ uniformly. The electric field and the electric potential at the centre of the sphere are respectively [$\epsilon_0 =$ permittivity of free space].

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