A parallel plate capacitor with oil (dielectr | vedclass

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(D) The capacitance of a parallel plate capacitor with a dielectric medium is given by $C = \frac{K \varepsilon_{0} A}{d}$.Here,$K$ is the dielectric

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$\frac{C}{2}$

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(D) The capacitance of a parallel plate capacitor with a dielectric medium is given by $C = \frac{K \varepsilon_{0} A}{d}$.Here,$K$ is the dielectric constant,$\varepsilon_{0}$ is the permittivity of free space,$A$ is the area of the plates,and $d$ is the distance between them.Given that with oil $(K = 2)$,the capacitance is $C = \frac{2 \varepsilon_{0} A}{d}$.When the oil is removed,the medium becomes air (or vacuum) with $K = 1$. Let the new capacitance be $C_{0}$.Then,$C_{0} = \frac{\varepsilon_{0} A}{d}$.Comparing the two equations,we get $C = 2 C_{0}$,which implies $C_{0} = \frac{C}{2}$.

$A$ parallel plate capacitor with oil (dielectric constant $K = 2$) between the plates has capacitance $C$. If the oil is removed,the capacitance of the capacitor becomes:

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