(A) The potential gradient $K$ of the potentiometer wire is given by:$K = \frac{V_{wire}}{L} = \frac{E_{driving} \times R}{(R + r) L}$Given $E_{drivin

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

(A) The potential gradient $K$ of the potentiometer wire is given by:$K = \frac{V_{wire}}{L} = \frac{E_{driving} \times R}{(R + r) L}$Given $E_{driving} = 5 \, V$, $r = 4 \, \Omega$, $L = 5 \, m$, and $R = 16 \, \Omega$:$K = \frac{5 \times 16}{(16 + 4) \times 5} = \frac{80}{100} = 0.8 \, V/m$Case $1$: Cells assist each other $(E_{net} = E_1 + E_2)$$E_1 + E_2 = K l_1$$1.3 + 1.1 = 0.8 \times l_1$$2.4 = 0.8 \times l_1 \implies l_1 = 3 \, m$Case $2$: Cells oppose each other $(E_{net} = E_1 - E_2)$$E_1 - E_2 = K l_2$$1.3 - 1.1 = 0.8 \times l_2$$0.2 = 0.8 \times l_2 \implies l_2 = 0.25 \, m$Thus, the balancing lengths are $3 \, m$ and $0.25 \, m$.

Class 12 Physics Current Electricity Potentiometer

Difficult

$A$ potentiometer wire has a length of $5 \, m$ and a resistance of $16 \, \Omega$. The driving cell has an e.m.f. of $5 \, V$ and an internal resistance of $4 \, \Omega$. When two cells of e.m.f.s $1.3 \, V$ and $1.1 \, V$ are connected so as to assist each other and then oppose each other, the balancing lengths are respectively:

MHT CET 2023 All MHT CET

A
$3 \, m, 0.25 \, m$
B
$0.25 \, m, 3 \, m$
C
$2.5 \, m, 0.3 \, m$
D
$0.3 \, m, 2.5 \, m$

Explore More

Browse All

Question Bank

All Subjects

Class 12 Questions

Class 12

Physics Questions

Chapter

Current Electricity

Subtopic

Potentiometer

Previous Year

MHT CET 2023 Paper All MHT CET years →

$A$ potentiometer wire has a length of $4 \ m$ and a resistance of $10 \ \Omega$. It is connected to a cell of $2 \ V$ emf. The potential gradient (potential difference per unit length) of the wire is: (in $V/m$)

Easy

View Solution

The wire of a potentiometer has a resistance of $4 \Omega$ and a length of $1 \ m$. It is connected to a cell of emf $2 \ V$ and internal resistance $1 \Omega$. The current flowing through the potentiometer wire is: (in $A$)

MediumAP EAMCET 2020

View Solution

$A$ wire,$10 \ m$ long,has a resistance of $40 \ \Omega$. It is connected in series with a resistance box of resistance $R$ and a $2 \ V$ storage cell. If the potential gradient along the wire is $0.1 \ mV/cm$,then the value of $R$ is (in $Omega$)

EasyTS EAMCET 2021

View Solution

In a potentiometer,a wire of length $10 \ m$ having resistance $50 \ \Omega$ is used. $A$ battery of $5 \ V$ and a resistor of $450 \ \Omega$ are connected in series to the wire. If an unknown battery of emf $E$ balances the potentiometer at $450 \ cm$,then the value of $E$ is (in $V$)

EasyAP EAMCET 2018

View Solution

The area of cross-section of a potentiometer wire is $6 \times 10^{-7} \ m^2$. The potential difference per unit length of the potentiometer wire when it is connected to a cell of negligible internal resistance and a resistor in series is $0.15 \ Vm^{-1}$. If the current through the potentiometer wire is $0.3 \ A$,then the resistivity of the material of the potentiometer wire is:

MediumTS EAMCET 2025

View Solution

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial

For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free

For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo

Similar Questions

$A$ potentiometer wire has a length of $4 \ m$ and a resistance of $10 \ \Omega$. It is connected to a cell of $2 \ V$ emf. The potential gradient (potential difference per unit length) of the wire is: (in $V/m$)

The wire of a potentiometer has a resistance of $4 \Omega$ and a length of $1 \ m$. It is connected to a cell of emf $2 \ V$ and internal resistance $1 \Omega$. The current flowing through the potentiometer wire is: (in $A$)

$A$ wire,$10 \ m$ long,has a resistance of $40 \ \Omega$. It is connected in series with a resistance box of resistance $R$ and a $2 \ V$ storage cell. If the potential gradient along the wire is $0.1 \ mV/cm$,then the value of $R$ is (in $Omega$)

In a potentiometer,a wire of length $10 \ m$ having resistance $50 \ \Omega$ is used. $A$ battery of $5 \ V$ and a resistor of $450 \ \Omega$ are connected in series to the wire. If an unknown battery of emf $E$ balances the potentiometer at $450 \ cm$,then the value of $E$ is (in $V$)

Vedclass Test Series

Exam Paper Generator

Online Exam Module