$A$ battery of $6 \text{ V}$ is connected to the ends of a uniform wire $3 \text{ m}$ long and of resistance $100 \Omega$. The potential difference between two points $50 \text{ cm}$ apart on the wire is: (in $\text{ V}$)

  • A
    $1$
  • B
    $2$
  • C
    $1.5$
  • D
    $3$

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Assertion : In a simple battery circuit,the point of the lowest potential is the negative terminal of the battery.
Reason : The current flows towards the point of the higher potential,as it does in such a circuit from the negative to the positive terminal.

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In the given circuit,if the current flowing through the $5 \Omega$ resistor is $0.5 \text{ A}$,then the value of $E$ is: (in $\text{ V}$)

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