$A$ bullet is fired from a gun. It hits a solid block resting on a frictionless surface,gets embedded into it,and both move jointly. In this process,

  • A
    Both momentum and kinetic energy are not conserved.
  • B
    Only kinetic energy is conserved.
  • C
    Both momentum and kinetic energy are conserved.
  • D
    Only momentum is conserved.

Explore More

Similar Questions

$A$ block of mass $m$ moving along a straight line with constant velocity $3 \vec{V}$ collides with another block of the same mass at rest. They stick together and move with a common velocity. The common velocity is:

$A$ moving body of mass $m$ and velocity $3 \, km/h$ collides with a body of mass $2m$ at rest and sticks to it. Now the combined mass starts to move. What will be the combined velocity in $km/h$?

$A$ clay ball of mass $m$ and speed $v$ strikes another metal ball of the same mass $m$,which is at rest. They stick together after the collision. The kinetic energy of the system after the collision is

$A$ block of mass $0.50 \ kg$ is moving with a speed of $2.00 \ m/s$ on a smooth surface. It strikes another mass of $1.00 \ kg$ at rest and then they move together as a single body. The energy loss during the collision is ............. $J$.

$A$ bullet of mass $m$ travelling with a speed $v$ hits a block of mass $M$ initially at rest and gets embedded in it. The combined system is free to move and there is no other force acting on the system. The heat generated in the process will be

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo