A parallel plate capacitor has plate area 40 | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The system can be viewed as two capacitors in series: one with the dielectric and one with the air gap.$C_1 = \frac{K \varepsilon_0 A}{t} = \frac{

Vedclass · Accepted Answer

$\frac{10}{3} \ \varepsilon_0 \ F$

Vedclass · Answer

(C) The system can be viewed as two capacitors in series: one with the dielectric and one with the air gap.$C_1 = \frac{K \varepsilon_0 A}{t} = \frac{5 \varepsilon_0 	imes 40 	imes 10^{-4}}{1 	imes 10^{-3}} = 20 \varepsilon_0 \ F$$C_2 = \frac{\varepsilon_0 A}{d-t} = \frac{\varepsilon_0 	imes 40 	imes 10^{-4}}{1 	imes 10^{-3}} = 4 \varepsilon_0 \ F$Since they are in series,the equivalent capacitance $C_{eq}$ is given by:$\frac{1}{C_{eq}} = \frac{1}{C_1} + \frac{1}{C_2} = \frac{1}{20 \varepsilon_0} + \frac{1}{4 \varepsilon_0}$$\frac{1}{C_{eq}} = \frac{1 + 5}{20 \varepsilon_0} = \frac{6}{20 \varepsilon_0} = \frac{3}{10 \varepsilon_0}$$C_{eq} = \frac{10}{3} \varepsilon_0 \ F$

$A$ parallel plate capacitor has plate area $40 \ cm^2$ and plate separation $2 \ mm$. The space between the plates is filled with a dielectric medium of thickness $1 \ mm$ and dielectric constant $5$. The capacitance of the system is ($\varepsilon_0 =$ permittivity of vacuum)

Similar Questions

The distance between the plates of a parallel plate capacitor is $8\,mm$ and the potential difference $(P.D.)$ is $120\,V$. If a $6\,mm$ thick slab of dielectric constant $K = 6$ is introduced between its plates,then:

$A$ parallel plate capacitor with plate area $A$ and separation $d$ is filled with two dielectric materials as shown in the figure. The dielectric constants are $K_1$ and $K_2$ respectively. The capacitance will be:

$A$ parallel plate air capacitor has capacity $C$ farad,potential $V$ volt,and energy $E$ joule. When the gap between the plates is completely filled with a dielectric material of dielectric constant $K > 1$,what happens to the potential $V$ and energy $E$?

Vedclass Test Series

Exam Paper Generator

Online Exam Module