(B) Given: Resistance $R = 450 \Omega$,Inductance $L = 1.5 \text{ H}$,Frequency $f = \frac{150}{\pi} \text{ Hz}$.The inductive reactance $X_L$ is give

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(B) Given: Resistance $R = 450 \Omega$,Inductance $L = 1.5 \text{ H}$,Frequency $f = \frac{150}{\pi} \text{ Hz}$.The inductive reactance $X_L$ is given by $X_L = \omega L = 2\pi f L$.Substituting the values: $X_L = 2 \pi \times \left(\frac{150}{\pi}\right) \times 1.5 = 2 \times 150 \times 1.5 = 300 \times 1.5 = 450 \Omega$.The phase difference $\phi$ between voltage and current in an $RL$ circuit is given by $\tan \phi = \frac{X_L}{R}$.Substituting the values: $\tan \phi = \frac{450}{450} = 1$.Therefore,$\phi = \tan^{-1}(1)$.

Class 12 Physics Alternating Current RL, RC and LC AC Circuits

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$A$ coil of resistance $450 \Omega$ and self-inductance $1.5 \text{ H}$ is connected to an $A$.$C$. source of frequency $\frac{150}{\pi} \text{ Hz}$. The phase difference between voltage and current is

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A
$\tan^{-1}(0.5)$
B
$\tan^{-1}(1)$
C
$\tan^{-1}(1.5)$
D
$\tan^{-1}(2.0)$

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Alternating Current

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RL, RC and LC AC Circuits

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$A$ coil of resistance $450 \Omega$ and self-inductance $1.5 \text{ H}$ is connected to an $A$.$C$. source of frequency $\frac{150}{\pi} \text{ Hz}$. The phase difference between voltage and current is

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For a series $LCR$ circuit with $R=100\,\Omega$,$L=0.5\,mH$ and $C=0.1\,pF$ connected across $220\,V-50\,Hz$ $AC$ supply,the phase angle between current and supplied voltage and the nature of the circuit is:

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