$a$ and $b$ are non-collinear vectors. If $c=(x-2)a+b$ and $d=(2x+1)a-b$ are collinear vectors,then the value of $x = \ldots$

  • A
    $\frac{1}{2}$
  • B
    $\frac{1}{4}$
  • C
    $\frac{1}{5}$
  • D
    $\frac{1}{3}$

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