$A$ solution of $8 \ g$ of a certain organic compound in $2 \ dm^3$ of water develops an osmotic pressure of $0.6 \ atm$ at $300 \ K$. Calculate the molar mass of the compound. $\left[R = 0.082 \ atm \ dm^3 \ K^{-1} \ mol^{-1}\right]$

The value of osmotic pressure of a $0.2 \ M$ aqueous solution at $293 \ K$ is ........... $atm$.

$A$ solution in which red blood cells can remain in their normal form is called ......

$A$ solution is prepared by dissolving $0.3 \ g$ of a non-volatile non-electrolyte solute '$A$' of molar mass $60 \ g \ mol^{-1}$ and $0.9 \ g$ of a non-volatile non-electrolyte solute '$B$' of molar mass $180 \ g \ mol^{-1}$ in $100 \ mL$ $H_2O$ at $27^{\circ}C$. Osmotic pressure of the solution will be
[Given: $R=0.082 \ L \ atm \ K^{-1} \ mol^{-1}$] (in $atm$)

$A$ solution contains a non-volatile solute of molecular mass $M_p$. Which of the following can be used to calculate the molecular mass of the solute in terms of osmotic pressure ($m = \text{Mass of solute}$,$V = \text{Volume of solution}$,and $\pi = \text{Osmotic pressure}$)?

At $27^{\circ} C$,the osmotic pressure of a solution containing $4 \ g$ of a non-electrolyte solute in $1.0 \ L$ of solution is $0.4 \ bar$. The molar mass of the solute in $g \ mol^{-1}$ is :
$(R=0.083 \ L \ bar \ K^{-1} \ mol^{-1})$