$0.2$ molal aqueous solution of $KCl$ freezes at $-0.680^{\circ} C$. Calculate van't Hoff factor for this solution. $(K_{f} = 1.86 \ K \ kg \ mol^{-1})$

The van't Hoff factor $i$ for a compound which undergoes dissociation in one solvent and association in other solvent is respectively

The van't Hoff factor $i$ for a compound which undergoes dissociation in one solvent and association in another solvent is respectively:

Acetic acid dissolved in benzene shows a molecular mass of

$75.2 \ g$ of phenol is added to $1 \ kg$ of solvent. The depression in freezing point is $7 \ K$. If phenol undergoes dimerization,calculate the percentage of association. $(K_f = 14 \ K \ kg \ mol^{-1})$

Benzoic acid undergoes dimerization in benzene. $x \ g$ of benzoic acid (molar mass $122 \ g \ mol^{-1}$) is dissolved in $49 \ g$ of benzene. The depression in freezing point is $1.12 \ K$. If the degree of association of the acid is $88 \%$,what is the value of $x$? ($K_f$ for benzene $= 4.9 \ K \ kg \ mol^{-1}$)