$A$ compound made of elements $A$ and $B$ forms an $fcc$ structure. Atoms of $A$ are at the corners and atoms of $B$ are present at the centres of the faces of the cube. What is the formula of the compound?

  • A
    $AB$
  • B
    $AB_2$
  • C
    $AB_3$
  • D
    $A_2B$

Explore More

Similar Questions

If an atom is present in the centre of the cube,the participation of that atom per unit cell is

The number of close neighbours in a body-centred cubic $(BCC)$ lattice of identical spheres is:

An ionic solid $AB$ crystallizes in a $NaCl$-type structure,where $A$ ions are at the corners of the cube. If all face-centered ions along one axis are removed,then the stoichiometry of the resulting solid will be .....

Difficult
View Solution

The number of octahedral voids in a $BCC$ structure is:

Determine the number of atoms per unit cell in a body-centered cubic $(BCC)$ unit cell.

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo