A compound contains atoms of x, y and z eleme | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) For a compound to be electrically neutral,the sum of the oxidation numbers of all atoms must be zero. Let the formula be $X_a(Y_bZ_c)_d$. Checking

Vedclass · Accepted Answer

$X_3(YZ_4)_3$

Vedclass · Answer

(C) For a compound to be electrically neutral,the sum of the oxidation numbers of all atoms must be zero. Let the formula be $X_a(Y_bZ_c)_d$. Checking option $C$: $X_3(YZ_4)_3$. Oxidation state of $X = +3$,$Y = +5$,$Z = -2$. Total charge $= 3(+3) + 3(+5 + 4(-2)) = 9 + 3(5 - 8) = 9 + 3(-3) = 9 - 9 = 0$. Since the sum of oxidation numbers is zero,$X_3(YZ_4)_3$ is a possible formula.

$A$ compound contains atoms of $x, y$ and $z$ elements. Oxidation numbers of $x, y$ and $z$ are $+3, +5$ and $-2$ respectively. Identify the possible formula of this compound?

Similar Questions

The oxidation number of nitrogen in $NH_2OH$ is

Oxidation numbers of $P$ in $PO_4^{3-}$,of $S$ in $SO_4^{2-}$ and that of $Cr$ in $Cr_2O_7^{2-}$ are respectively

In $Pb_3O_4$,the different oxidation states of $Pb$ are:

The oxidation state of $Fe$ in $Fe_3O_4$ is:

What is the change in the oxidation state of nitrogen when $HNO_3$ is converted into $N_2O$?

Vedclass Test Series

Exam Paper Generator

Online Exam Module