$2,2-$dichloropropane $\stackrel{Aq. KOH}{\longrightarrow} A$ $\xrightarrow{\text{Clemmensen reduction}} B$. $B$ is

Ketone reacts with $NH_2OH$ to give oxime. The reaction is as follows:
$R_2C=O + H_2N-OH \rightarrow R_2C=N-OH + H_2O$
The total number of organic products (ketoxime) formed when the simplest ketone and its next higher homologue react with $NH_2OH$,is:

Formaldehyde reacts with methyl magnesium iodide to form an additive product,which upon aqueous hydrolysis yields:

Given below are two statements: Statement $I$: The condensation reaction between $CH_{3} - CH = O$ and $H_{2}N - NH - C(=O) - NH_{2}$ under optimum pH will produce $CH_{3} - CH = N - N(H) - C(=O) - NH_{2}$. Statement $II$: The molecule,$Ph - CH(OH)(OCH_{3})$ will generate $Ph - CH = O$ in the presence of dilute acid. In the light of the above statements,choose the correct answer from the options given below:

Acetone is treated with excess of ethanol in the presence of hydrochloric acid. The product obtained is

The reactant is $3$-methylpentanal. The reaction with $NaCN$ followed by $H_2SO_4$ (cyanohydrin formation) is shown below:
$CH_3CH_2CH(CH_3)CH_2CHO \xrightarrow{NaCN/H^+} CH_3CH_2CH(CH_3)CH_2CH(OH)CN$
Products of the reaction are: