(C) The number of half-lives $(n)$ is calculated as: $n = \frac{\text{total time}}{\text{half-life period}} = \frac{90 \ min}{30 \ min} = 3$. The numb

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(C) The number of half-lives $(n)$ is calculated as: $n = \frac{\text{total time}}{\text{half-life period}} = \frac{90 \ min}{30 \ min} = 3$. The number of remaining atoms $(N)$ is given by the formula: $N = N_0 \times (\frac{1}{2})^n$. Substituting the values: $N = 600 \times (\frac{1}{2})^3$. $N = 600 \times \frac{1}{8} = 75 \ atoms$.

Class 12 Chemistry Nuclear Chemistry Rate of decay and Half-life

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$A$ certain nuclide has a half-life period of $30 \ min$. If a sample containing $600$ atoms is allowed to decay for $90 \ min$,how many atoms will remain (in $atoms$)?

MHT CET 2007 All MHT CET

A
$200$
B
$450$
C
$75$
D
$150$

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Nuclear Chemistry

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Rate of decay and Half-life

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$A$ certain nuclide has a half-life period of $30 \ min$. If a sample containing $600$ atoms is allowed to decay for $90 \ min$,how many atoms will remain (in $atoms$)?

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The $t_{1/2}$ of a radioactive element is $20 \ min$. The time interval between the stages of its $33\%$ and $67\%$ decay is ....... $min$.

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