$4s^2$ is the configuration of the outermost orbit of an element. Its atomic number would be $:-$

The value of the azimuthal quantum number for electrons present in the $4p$ orbital is:

The maximum number of sub-levels,orbitals and electrons in $N$ shell of an atom are respectively

The maximum probability of finding an electron in the $d_{xy}$ orbital is

Which of the following orbitals are possible: $1p, 2s, 2p, 3f$?

For a hydrogen atom,the orbital$(s)$ with the lowest energy is/are:
$A$. $4s$
$B$. $3p_x$
$C$. $3d_{x^2-y^2}$
$D$. $3d_{z^2}$
$E$. $4p_z$
Choose the correct answer from the options given below: