A ball is thrown vertically upwards with a ve | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) Let the maximum height reached by the ball be $H$. At the maximum height,the final velocity is $0$. Using the equation of motion $v_f^2 = v_i^2 -

Vedclass · Accepted Answer

$ \frac{v}{\sqrt{2}}, \frac{E}{2} $

Vedclass · Answer

(B) Let the maximum height reached by the ball be $H$. At the maximum height,the final velocity is $0$. Using the equation of motion $v_f^2 = v_i^2 - 2gH$,we get $0 = v^2 - 2gH$,which implies $H = \frac{v^2}{2g}$.At half the height,$h = \frac{H}{2} = \frac{v^2}{4g}$.Using the equation $v'^2 = v^2 - 2gh$,the velocity $v'$ at height $h$ is $v'^2 = v^2 - 2g(\frac{v^2}{4g}) = v^2 - \frac{v^2}{2} = \frac{v^2}{2}$.Thus,$v' = \frac{v}{\sqrt{2}}$.The kinetic energy $E'$ at this point is $E' = \frac{1}{2}mv'^2 = \frac{1}{2}m(\frac{v^2}{2}) = \frac{1}{2}(\frac{1}{2}mv^2) = \frac{E}{2}$.

$A$ ball is thrown vertically upwards with a velocity $v$ and an initial kinetic energy $E$. When it reaches half way to the top of its flight,what are its velocity and kinetic energy respectively?

Similar Questions

When the speed of a vehicle increases by $2 \ m/s$,its kinetic energy doubles. What is the original speed of the vehicle?

If the momentum of an object is doubled,what is the percentage increase in its kinetic energy (in $\%$)?

If the linear momentum is increased by $5\%$,the kinetic energy will increase by.......$\%$

The kinetic energy of a light body and a heavy body is same. Which one of them has greater momentum?

The graph between kinetic energy $E$ and velocity $v$ is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module