A cylindrical conductor of radius R carries a | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) For a cylindrical conductor of radius $R$, the magnetic field inside at a distance $r < R$ is given by $B_{in} = \frac{\mu_0 i r}{2 \pi R^2}$.Give

Vedclass · Accepted Answer

$\frac{8}{3} \ T$

Vedclass · Answer

(B) For a cylindrical conductor of radius $R$, the magnetic field inside at a distance $r Given that the point is $R/4$ inside from the surface, the distance from the center is $r = R - R/4 = 3R/4$.Thus, $B_{in} = \frac{\mu_0 i (3R/4)}{2 \pi R^2} = \frac{3 \mu_0 i}{8 \pi R} = 10 \ T$.From this, we find $\frac{\mu_0 i}{2 \pi R} = \frac{10 	imes 4}{3} = \frac{40}{3} \ T$.For a point outside at a distance $4R$ from the surface, the distance from the center is $r' = R + 4R = 5R$.The magnetic field outside is $B_{out} = \frac{\mu_0 i}{2 \pi r'} = \frac{\mu_0 i}{2 \pi (5R)} = \frac{1}{5} \left( \frac{\mu_0 i}{2 \pi R} ight)$.Substituting the value, $B_{out} = \frac{1}{5} 	imes \frac{40}{3} = \frac{8}{3} \ T$.

$A$ cylindrical conductor of radius $R$ carries a current $i$. The value of the magnetic field at a point, which is $R/4$ distance inside from the surface, is $10 \ T$. Find the value of the magnetic field at a point, which is $4R$ distance outside from the surface.

Similar Questions

$A$ horizontal overhead powerline is at a height of $5 \,m$ from the ground and carries a current of $150 \,A$ from East to West. The magnetic field directly below it on the ground is

$A$ long straight wire carries a current along the $x$-axis. Consider the points $A(0, 1, 0)$,$B(0, 1, 1)$,$C(1, 0, 1)$,and $D(1, 1, 1)$. Which of the following pairs of points will have magnetic fields of the same magnitude?

If the strength of the magnetic field produced $10\,cm$ away from an infinitely long straight conductor is ${10^{ - 5}}\,Wb/m^2$,the value of the current flowing in the conductor will be........$A$.

The magnetic field at the centre of a coil of $n$ turns,bent in the form of a square of side $2l$,carrying current $i$,is

Two wires $A$ and $B$ are of lengths $40 \ cm$ and $30 \ cm$. $A$ is bent into a circle of radius $r$ and $B$ into an arc of radius $r$. $A$ current $i_1$ is passed through $A$ and $i_2$ through $B$. To have the same magnetic inductions at the centre,the ratio of $i_1: i_2$ is

Vedclass Test Series

Exam Paper Generator

Online Exam Module