(i) Label A, B, C and D.(ii) How many CO_2 mo | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) In the Krebs cycle ($TCA$ cycle):$1$. Acetyl CoA combines with Oxaloacetic acid to form $A = 	ext{Citric acid}$.$2$. $\alpha$-Ketoglutaric acid i

Vedclass · Accepted Answer

$(i) A=	ext{Citric acid}, B=CO_2, C=	ext{Succinic acid}, D=FADH_2 \ (ii) \ 2 CO_2$

Vedclass · Answer

(B) In the Krebs cycle ($TCA$ cycle):$1$. Acetyl CoA combines with Oxaloacetic acid to form $A = 	ext{Citric acid}$.$2$. $\alpha$-Ketoglutaric acid is converted to $C = 	ext{Succinyl CoA}$,releasing $B = CO_2$ and producing $NADH+H^+$.$3$. Succinyl CoA is converted to Succinic acid,producing $GTP$ (or $ATP$).$4$. Succinic acid is converted to Fumaric acid,producing $D = FADH_2$.$5$. Fumaric acid is converted to Malic acid.$6$. Between Citric acid $(A)$ and Malic acid,two molecules of $CO_2$ are released (one during the conversion of Isocitric acid to $\alpha$-Ketoglutaric acid and one during the conversion of $\alpha$-Ketoglutaric acid to Succinyl CoA).Therefore,the correct labels are $A = 	ext{Citric acid}, B = CO_2, C = 	ext{Succinyl CoA}, D = FADH_2$ and the number of $CO_2$ molecules evolved is $2$.

$(i)$ Label $A, B, C$ and $D$.
$(ii)$ How many $CO_2$ molecules are evolved between $A$ and Malic acid?
Choose the correct option from the following regarding the answers to the above questions $:-$

Similar Questions

Kreb's cycle is also known as

Select the correct statement with respect to the Krebs cycle.

Which of the following is the correct sequence in the $Krebs$ cycle?

In $Kreb's$ cycle, $FAD$ acts as an electron acceptor during the conversion of:

The citric acid cycle begins with the reaction . . . . . . .

Vedclass Test Series

Exam Paper Generator

Online Exam Module

$(i)$ Label $A, B, C$ and $D$.$(ii)$ How many $CO_2$ molecules are evolved between $A$ and Malic acid?Choose the correct option from the following regarding the answers to the above questions $:-$