[NiCl_4]^{2-} and [Ni(CN)_4]^{2-} show simila | vedclass

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(D) In both complexes,the oxidation state of $Ni$ is calculated as follows:For $[NiCl_4]^{2-}$: $x + 4(-1) = -2 \Rightarrow x = +2$.For $[Ni(CN)_4]^{2

Vedclass · Accepted Answer

Primary valency of $Ni$

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(D) In both complexes,the oxidation state of $Ni$ is calculated as follows:For $[NiCl_4]^{2-}$: $x + 4(-1) = -2 \Rightarrow x = +2$.For $[Ni(CN)_4]^{2-}$: $x + 4(-1) = -2 \Rightarrow x = +2$.The oxidation state of the central metal ion is referred to as the primary valency.Therefore,both complexes show similarity in the primary valency of $Ni$.

$[NiCl_4]^{2-}$ and $[Ni(CN)_4]^{2-}$ show similarity in

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