60 words can be made using all the letters of | vedclass

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(C) The word is $BHBJO$. The letters are $B, B, H, J, O$. Total letters = $5$. The number of arrangements is $\frac{5!}{2!} = \frac{120}{2} = 60$.To f

Vedclass · Accepted Answer

$OBBJH$

Vedclass · Answer

(C) The word is $BHBJO$. The letters are $B, B, H, J, O$. Total letters = $5$. The number of arrangements is $\frac{5!}{2!} = \frac{120}{2} = 60$.To find the $50^{	ext{th}}$ word,we arrange them alphabetically: $B, B, H, J, O$.$1$. Words starting with $B$: $\frac{4!}{1!} = 24$ words.$2$. Words starting with $H$: $\frac{4!}{2!} = 12$ words. (Total = $24 + 12 = 36$)$3$. Words starting with $J$: $\frac{4!}{2!} = 12$ words. (Total = $36 + 12 = 48$)$4$. Words starting with $O$:- $OBBJH$ $(49^{	ext{th}})$- $OBBJH$ is not correct,let's list $O$ words:- $OBBHJ$ $(49^{	ext{th}})$- $OBBJH$ $(50^{	ext{th}})$Thus,the $50^{	ext{th}}$ word is $OBBJH$.

$60$ words can be made using all the letters of the word $BHBJO$,with or without meaning. If these words are written as in a dictionary,then the $50^{\text{th}}$ word is:

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